Landauer formula

Conductance formula in terms of the conductance quantum and transmission possibilities

In mesoscopic physics, the Landauer formula—named after Rolf Landauer, who first suggested its prototype in 1957[1]—is a formula relating the electrical resistance of a quantum conductor to the scattering properties of the conductor.[2] It is the equivalent of Ohm's law for mesoscopic circuits with spatial dimensions in the order of or smaller than the phase coherence length of charge carriers (electrons and holes). In metals, the phase coherence length is of the order of the micrometre for temperatures less than 1 K.[3]

Description

In the simplest case where the system only has two terminals, and the scattering matrix of the conductor does not depend on energy, the formula reads

G ( μ ) = G 0 n T n ( μ )   , {\displaystyle G(\mu )=G_{0}\sum _{n}T_{n}(\mu )\ ,}

where G {\displaystyle G} is the electrical conductance, G 0 = e 2 / ( π ) 7.75 × 10 5 Ω 1 {\displaystyle G_{0}=e^{2}/(\pi \hbar )\approx 7.75\times 10^{-5}\Omega ^{-1}} is the conductance quantum, T n {\displaystyle T_{n}} are the transmission eigenvalues of the channels, and the sum runs over all transport channels in the conductor. This formula is very simple and physically sensible: The conductance of a nanoscale conductor is given by the sum of all the transmission possibilities that an electron has when propagating with an energy equal to the chemical potential, E = μ {\displaystyle E=\mu } .[4]

Multiple terminals

A generalization of the Landauer formula for multiple terminals is the Landauer–Büttiker formula,[5][4] proposed by Markus Büttiker [de]. If terminal j {\displaystyle j} has voltage V j {\displaystyle V_{j}} (that is, its chemical potential is e V j {\displaystyle eV_{j}} and differs from terminal i {\displaystyle i} chemical potential), and T i , j {\displaystyle T_{i,j}} is the sum of transmission probabilities from terminal i {\displaystyle i} to terminal j {\displaystyle j} (note that T i , j {\displaystyle T_{i,j}} may or may not equal T j , i {\displaystyle T_{j,i}} depending on the presence of a magnetic field), the net current leaving terminal i {\displaystyle i} is

I i = e 2 2 π j ( T j , i V i T i , j V j ) {\displaystyle I_{i}={\frac {e^{2}}{2\pi \hbar }}\sum _{j}\left(T_{j,i}V_{i}-T_{i,j}V_{j}\right)}

In the case of a system with two terminals, the contact resistivity symmetry yields

i j T i j = i j T j i {\displaystyle \sum _{i\neq j}T_{ij}=\sum _{i\neq j}T_{ji}}

and the generalized formula can be rewritten as

I i = e 2 2 π i j T j i ( V i V j ) {\displaystyle I_{i}={\frac {e^{2}}{2\pi \hbar }}\sum _{i\neq j}T_{ji}(V_{i}-V_{j})}

which leads us to

I 1 = e 2 2 π T 12 ( V 1 V 2 ) = I 2 = e 2 2 π T 21 ( V 2 V 1 ) {\displaystyle I_{1}={\frac {e^{2}}{2\pi \hbar }}T_{12}(V_{1}-V_{2})=-I_{2}=-{\frac {e^{2}}{2\pi \hbar }}T_{21}(V_{2}-V_{1})}

which implies that the scattering matrix of a system with two terminals is always symmetrical, even with the presence of a magnetic field. The reversal of the magnetic field will only change the propagation direction of the edge states, without affecting the transmission probability.

Example

Three contact system for electron transport

As an exemple, in a three contact system, the net current leaving the contact 1 can be written as

I 1 = ( ( T 21 + T 31 ) V 1 T 12 V 2 T 13 V 3 ) {\displaystyle I_{1}=\left((T_{21}+T_{31})V_{1}-T_{12}V_{2}-T_{13}V_{3}\right)}

Which is the carriers leaving contact 1 with a potential V 1 {\displaystyle V_{1}} from which we substract the carriers from contacts 2 and 3 with potentials V 2 {\displaystyle V_{2}} and V 3 {\displaystyle V_{3}} respectively, going into contact 1.

In the absence of an applied magnetic field, the generalized equation would be the result of applying Kirchoff's law to a system of conductance G i j = ( e 2 ) / ( 2 π ) T i j {\displaystyle G_{ij}=(e^{2})/(2\pi \hbar )T_{ij}} . However, in the presence of a magnetic field, the time reversal symmetry would be broken and therefore, T i j T j i {\displaystyle T_{ij}\neq T_{ji}} .

In the presence of more than two terminals in the system, the two terminals symmetry is broken. In the earlier given exemple, T 21 T 32 + T 13 {\displaystyle T_{21}\neq T_{32}+T_{13}} . This is due to the fact that the terminals "recycle" the incoming electrons, for which the phase coherence is lost when another electron is emitted towards terminal 1. However, since the carriers are moving through edge states, one can see that T 21 B = T 12 B {\displaystyle T_{21}^{B}=T_{12}^{-B}} even with the presence of a third terminal. This is due to the fact that under magnetic field inversion, the edge states simply change their propagation orientation. This is especially true if terminal 3 is taken as a perfect potential probe.

See also

References

  1. ^ Landauer, R. (1957). "Spatial Variation of Currents and Fields Due to Localized Scatterers in Metallic Conduction". IBM Journal of Research and Development. 1 (3): 223–231. doi:10.1147/rd.13.0223.
  2. ^ Nazarov, Y. V.; Blanter, Ya. M. (2009). Quantum transport: Introduction to Nanoscience. Cambridge University Press. pp. 29–41. ISBN 978-0521832465.
  3. ^ Akkermans, Eric; Montambaux, Gilles, eds. (2007), "Introduction: mesoscopic physics", Mesoscopic Physics of Electrons and Photons, Cambridge: Cambridge University Press, pp. 1–30, ISBN 978-0-521-85512-9, retrieved 2024-04-25
  4. ^ a b Büttiker, M. (1990). "Quantized Transmission of a Saddle-Point Constriction". Physical Review B. 41 (11): 7906–7909. doi:10.1103/PhysRevB.41.7906.
  5. ^ Bestwick, Andrew J. (2015). Quantum Edge Transport in Topological Insulators (Thesis). Stanford University.