1946 New Hampshire gubernatorial election

Election

1946 New Hampshire gubernatorial election

← 1944 November 5, 1946 1948 →
 
Nominee Charles M. Dale F. Clyde Keefe
Party Republican Democratic
Popular vote 103,204 60,247
Percentage 63.14% 36.86%

County results
Dale:      50-60%      60-70%      70-80%      80–90%

Governor before election

Charles M. Dale
Republican

Elected Governor

Charles M. Dale
Republican

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The 1946 New Hampshire gubernatorial election was held on November 5, 1946. Incumbent Republican Charles M. Dale defeated Democratic nominee F. Clyde Keefe with 63.14% of the vote.

Primary elections

Primary elections were held on August 6, 1946.[1]

Republican primary

Candidates

Results

Republican primary results[1]
Party Candidate Votes %
Republican Charles M. Dale (incumbent) 22,917 49.79
Republican Sherman Adams 22,732 49.39
Republican Elmer E. Bussey 375 0.82
Total votes 46,024 100.00

General election

Candidates

  • Charles M. Dale, Republican
  • F. Clyde Keefe, Democratic

Results

1946 New Hampshire gubernatorial election[2]
Party Candidate Votes % ±%
Republican Charles M. Dale (incumbent) 103,204 63.14%
Democratic F. Clyde Keefe 60,247 36.86%
Majority 42,957
Turnout 163,451
Republican hold Swing

References

  1. ^ a b Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved June 1, 2020.
  2. ^ Cook, Rhodes (November 5, 2013). America Votes 30: 2011-2012, Election Returns by State. ISBN 9781452290171. Retrieved June 1, 2020.
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