1890 United States House of Representatives election in Wyoming

1890 United States House of Representatives elections in Wyoming

September 11, 1890 (1890-09-11) 1892 →
 
Nominee Clarence D. Clark George T. Beck
Party Republican Democratic
Popular vote 9,087 6,520
Percentage 58.22% 41.78%

Elected U.S. Representative

Clarence D. Clark
Republican

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There were two United States House of Representatives elections in Wyoming in 1890, both held on September 11, 1890. Republican lawyer Clarence D. Clark defeated Democratic George T. Beck with 58.22% of the vote and became the first person to represent Wyoming in the House of Representatives.

Results

United States House of Representatives election in Wyoming, 1890[1]
Party Candidate Votes %
Republican Clarence D. Clark 9,087 58.22%
Democratic George T. Beck 6,520 41.78%
Total votes 15,607 100%

References

  1. ^ "United States House of Representatives election in Wyoming, 1890".


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